Print Spiral Pattern in Java
Programming is always a fun and creative task. The more creative you can think the better programmer you will become. However, programming isn’t always about solving problems sometimes there’s also a fun aspect to it which makes it way more satisfying. If you are a programmer then you might have already played with patterns, strings, etc multiple times. Well, it’s also likely that you are already familiar with printing patterns. So in today’s article, we will create a program to Print Spiral Pattern in Java. With the help of this program, you will be able to print a spiral pattern of integers using java language. Practising these types of questions also helps to get an upper edge in Competitive Programming
So open up your IDE and let’s get started real quick. Once you understand the logic practice this program on your own to make your brain work in a problem-solving way. This is a somewhat hard question you might get asked in an interview so make sure to practice it on your own after reading this article.
Also Read: How To Print Hello World in Java Without Semicolon
What’s The Approach?
Firstly we will create a 2D array with size n.
Next, we will create variables to store the boundary of array and size left to print the spiral.
Also, we are going to create a char variable to store the movement of the spiral pattern. It is like ‘r’ for right, ‘l’ for left, ‘d’ for down, and ‘u’ for up.
Now we will execute a loop from 1 to n*2 and will fill up the array in a spiral pattern.
Java Program To Print Spiral Pattern
Input: n = 5
public class TechDecodeTutorials { public static void printSpiral(int size) { // Create row and col // to traverse rows and columns int row = 0, col = 0; int boundary = size - 1; int sizeLeft = size - 1; int flag = 1; // Variable to determine the movement // r = right, l = left, d = down, u = upper char move = 'r'; // Array for matrix int matrix[][] = new int[size][size]; for (int i = 1; i < size * size + 1; i++) { // Assign the value matrix[row][col] = i; // switch-case to determine the next index switch (move) { // If right, go right case 'r': col += 1; break; // if left, go left case 'l': col -= 1; break; // if up, go up case 'u': row -= 1; break; // if down, go down case 'd': row += 1; break; } // Check if the matrix // has reached array boundary if (i == boundary) { // Add the left size for the next boundary boundary += sizeLeft; // If 2 rotations has been made, // decrease the size left by 1 if (flag != 2) { flag = 2; } else { flag = 1; sizeLeft -= 1; } // switch-case to rotate the movement switch (move) { // if right, rotate to down case 'r': move = 'd'; break; // if down, rotate to left case 'd': move = 'l'; break; // if left, rotate to up case 'l': move = 'u'; break; // if up, rotate to right case 'u': move = 'r'; break; } } } // Print the matrix for (row = 0; row < size; row++) { for (col = 0; col < size; col++) { int n = matrix[row][col]; System.out.print((n < 10) ? (n + " ") : (n + " ")); } System.out.println(); } } // Driver Code public static void main(String[] args) { // Get the size of size int size = 5; // Print the Spiral Pattern printSpiral(size); } }
Output:
1 2 3 4 5 16 17 18 19 6 15 24 25 20 7 14 23 22 21 8 13 12 11 10 9